Macros

What is macro? In its essence, macro is a function, which

1. takes as an input an expression (parsed input)
2. modify the expressions in argument
3. insert the modified expression at the same place as the one that is parsed.

Macros are necessary because they execute after the code is parsed (2nd step in conversion of source code to binary as described in last lect, after Meta.parse) therefore, macros allow the programmer to generate and include fragments of customized code before the full program is compiled run. Since they are executed during parsing, they do not have access to the values of their arguments, but only to their syntax.

To illustrate the difference, consider the following example:

A very convenient and highly recommended ways to write macros is to write functions modifying the Expression and then call that function in the macro. Let's demonstrate on an example, where every occurrence of sin is replaced by cos. We defined the function recursively traversing the AST and performing the substitution

replace_sin(x::Symbol) = x == :sin ? :cos : x
replace_sin(e::Expr) = Expr(e.head, map(replace_sin, e.args)...)
replace_sin(u) = u

and then we define the macro

macro replace_sin(ex)
	replace_sin(esc(ex))
end

@replace_sin(cosp1(x) = 1 + sin(x))
cosp1(1) == 1 + cos(1)

notice the following

• the definition of the macro is similar to the definition of the function with the exception that instead of the keyword function we use keyword macro
• when calling the macro, we signal to the compiler our intention by prepending the name of the macro with @.
• the macro receives the expression(s) as the argument instead of the evaluated argument and also returns an expression that is placed on the position where the macro has been called
• when you are using macro, you should be as a user aware that the code you are entering can be arbitrarily modified and you can receive something completely different. This meanst that @ should also serve as a warning that you are leaving Julia's syntax. In practice, it make sense to make things akin to how they are done in Julia or to write Domain Specific Language with syntax familiar in that domain.

Inspecting the lowered code

Meta.@lower @replace_sin( 1 + sin(x))

We observe that there is no trace of macro in lowered code (compare to Meta.@lower 1 + cos(x), which demonstrates that the macro has been expanded after the code has been parsed but before it has been lowered. In this sense macros are indispensible, as you cannot replace them simply by the combination of Meta.parse end eval. You might object that in the above example it is possible, which is true, but only because the effect of the macro is in the global scope.

ex = Meta.parse("cosp1(x) = 1 + sin(x)")
ex = replace_sin(ex)
eval(ex)

The following example cannot be achieved by the same trick, as the output of the macro modifies just the body of the function

function cosp2(x)
	@replace_sin 2 + sin(x)
end
cosp2(1) ≈ (2 + cos(1))

This is not possible

function parse_eval_cosp2(x)
	ex = Meta.parse("2 + sin(x)")
	ex = replace_sin(ex)
	eval(ex)
end

as can be seen from

julia> @code_lowered cosp2(1)
CodeInfo(
1 ─ %1 = Main.cos(x)
│   %2 = 2 + %1
└──      return %2
)

julia> @code_lowered parse_eval_cosp2(1)
CodeInfo(
1 ─ %1 = Base.getproperty(Main.Meta, :parse)
│        ex = (%1)("2 + sin(x)")
│        ex = Main.replace_sin(ex)
│   %4 = Main.eval(ex)
└──      return %4
)

add1(x) = x + 1
function redefine_add(x)
    eval(:(add1(x) = x - 1))
    add1(x)
end
julia> redefine_add(1)
2

julia> redefine_add(1)
0

Macros are quite tricky to debug. Macro @macroexpand allows to observe the expansion of macros. Observe the effect as

@macroexpand @replace_sin(cosp1(x) = 1 + sin(x))

What goes under the hood of macro expansion?

Let's consider that the compiler is compiling

function cosp2(x)
	@replace_sin 2 + sin(x)
end

First, Julia parses the code into the AST as

ex = Meta.parse("""
   function cosp2(x)
	   @replace_sin 2 + sin(x)
end
""") |> Base.remove_linenums!
dump(ex)

We observe that there is a macrocall in the AST, which means that Julia will expand the macro and put it in place

ex.args[2].args[1].head 	# the location of the macrocall
ex.args[2].args[1].args[1]  # which macro to call
ex.args[2].args[1].args[2]  # line number
ex.args[2].args[1].args[3]	# on which expression

We can manullay run replace_sin and insert it back on the relevant sub-part of the sub-tree

ex.args[2].args[1] = replace_sin(ex.args[2].args[1].args[3])
ex |> dump

now, ex contains the expanded macro and we can see that it correctly defines the function

eval(ex)

Calling macros

Macros can be called without parentheses

macro showarg(ex)
	println("single argument version")
	@show ex
	ex
end
@showarg(1 + 1)
@showarg 1 + 1

Macros use the very same multiple dispatch as functions, which allows to specialize macro calls

macro showarg(x1, x2::Symbol)
	println("two argument version, second is Symbol")
	@show x1
	@show x2
	x1
end
macro showarg(x1, x2::Expr)
	println("two argument version, second is Expr")
	@show x1
	@show x2
	x1
end
@showarg(1 + 1, x)
@showarg(1 + 1, 1 + 3)
@showarg 1 + 1, 1 + 3
@showarg 1 + 1  1 + 3

(the @showarg(1 + 1, :x) raises an error, since :(:x) is of Type QuoteNode).

Observe that macro dispatch is based on the types of AST that are handed to the macro, not the types that the AST evaluates to at runtime.

List of all defined versions of macro

methods(var"@showarg")

Notes on quotation

In the previous lecture we have seen that we can quote a block of code, which tells the compiler to treat the input as a data and parse it. We have talked about three ways of quoting code.

1. :(quoted code)
2. Meta.parse(input_string)
3. quote ... end

The truth is that Julia does not do full quotation, but a quasiquotation as it allows you to interpolate expressions inside the quoted code using $ symbol similar to the string. This is handy, as sometimes, when we want to insert into the quoted code an result of some computation / preprocessing. Observe the following difference in returned code

a = 5
:(x = a)
:(x = $(a))
let y = :x
    :(1 + y), :(1 + $y)
end

In contrast to the behavior of :() (or quote ... end, true quotation would not perform interpolation where unary $ occurs. Instead, we would capture the syntax that describes interpolation and produce something like the following:

(
    :(1 + x),                         # Quasiquotation
    Expr(:call, :+, 1, Expr(:$, :x)), # True quotation
)

for (v, f) in [(:sin, :foo_sin)]
	quote
		$(f)(x) = $(v)(x)
	end |> Base.remove_linenums! |> dump
end

When we need true quoting, i.e. we need something to stay quoted, we can use QuoteNode as

macro true_quote(e)
    QuoteNode(e)
end

let y = :x
    (
        @true_quote(1 + $y),
        :(1 + $y),
    )
end

At first glance, QuoteNode wrapper seems to be useless. But QuoteNode has clear value when it's used inside a macro to indicate that something should stay quoted even after the macro finishes its work. Also notice that the expression received by macro are quoted, not quasiquoted, since in the latter case $y would be replaced.

We can demonstrate it by defining a new macro no_quote which will just return the expression as is

macro no_quote(ex)
    ex
end

let y = :x
    @no_quote(1 + $y)
end

The error code snippet errors telling us that the expression "$" is outside of a quote block. This is because the macro @no_quote has returned a block with $ occuring outside of quote or string definition.

for f in [:setindex!, :getindex, :size, :length]
    @eval $(f)(A::MyMatrix, args...) = $(f)(A.x, args...)
end

Macros do not know about runtime values, they only know about syntax trees. When a macro receives an expression with a x in it, it can't interpolate the value of x into the syntax tree because it reads the syntax tree before x ever has a value!

Instead, when a macro is given an expression with $ in it, it assumes you're going to give your own meaning to x. In the case of BenchmarkTools.jl they return code that has to wait until runtime to receive the value of x and then splice that value into an expression which is evaluated and benchmarked. Nowhere in the actual body of the macro do they have access to the value of x though.

a = 5
s = "a = $(a)"
typoef(s)
println(s)
filename = "/tmp/test_of_interpolation"
run(`touch $(filename)`)

Macro hygiene

Macro hygiene is a term coined in 1986 addressing the following problem: if you're automatically generating code, it's possible that you will introduce variable names in your generated code that will clash with existing variable names in the scope in which a macro is called. These clashes might cause your generated code to read from or write to variables that you should not be interacting with. A macro is hygienic when it does not interact with existing variables, which means that when macro is evaluated, it should not have any effect on the surrounding code.

By default, all macros in Julia are hygienic which means that variables introduced in the macro have automatically generated names, where Julia ensures they will not collide with user's variable. These variables are created by gensym function / macro.

julia> gensym("hello")
Symbol("##hello#257")

Let's demonstrate it on our own version of an macro @elapsed which will return the time that was needed to evaluate the block of code.

macro tooclean_elapsed(ex)
	quote
		tstart = time()
		$(ex)
		time() - tstart
	end
end

fib(n) = n <= 1 ? n : fib(n-1) + fib(n - 2)
let 
	tstart = "should not change the value and type"
	t = @tooclean_elapsed r = fib(10)
	println("the evaluation of fib took ", t, "s and result is ", r)
	@show tstart
end

We see that variable r has not been assigned during the evaluation of macro. We have also used let block in orders not to define any variables in the global scope. The problem with the above is that it cannot be nested. Why is that? Let's observe how the macro was expanded

julia> Base.remove_linenums!(@macroexpand @tooclean_elapsed r = fib(10))
quote
    var"#12#tstart" = Main.time()
    var"#13#r" = Main.fib(10)
    Main.time() - var"#12#tstart"
end

We see that tstart in the macro definition was replaced by var"#12#tstart", which is a name generated by Julia's gensym to prevent conflict. The same happens to r, which was replaced by var"#13#r". This names are the result of Julia's hygiene-enforcing pass, which is intended to prevent us from overwriting existing variables during macro expansion. This pass usually makes our macros safer, but it is also a source of confusion because it introduces a gap between the expressions we generate and the expressions that end up in the resulting source code. Notice that in the case of tstart, we actually wanted to replace tstart with a unique name, such that if we by a bad luck define tstart in our code, it would not be affected, as we can see in this example.

let 
	tstart = "should not change the value and type "
	t = @tooclean_elapsed r = fib(10)
	println(tstart, "  ", typeof(tstart))
end

But in the second case, we would actually very much like the variable r to retain its name, such that we can accesss the results (and also, ex can access and change other local variables). Julia offer a way to escape from the hygienic mode, which means that the variables will be used and passed as-is. Notice the effect if we escape just the expression ex

macro justright_elapsed(ex)
	quote
		tstart = time()
		$(esc(ex))
		time() - tstart
	end
end

let 
	tstart = "should not change the value and type "
	t = @justright_elapsed r = fib(10)
	println("the evaluation of fib took ", t, "s and result is ", r)
	println(tstart, "  ", typeof(tstart))
end

which now works as intended. We can inspect the output again using @macroexpand

julia> Base.remove_linenums!(@macroexpand @justright_elapsed r = fib(10))
quote
    var"#19#tstart" = Main.time()
    r = fib(10)
    Main.time() - var"#19#tstart"
end

and compare it to Base.remove_linenums!(@macroexpand @justright_elapsed r = fib(10)). We see that the expression ex has its symbols intact. To use the escaping / hygience correctly, you need to have a good understanding how the macro evaluation works and what is needed. Let's now try the third version of the macro, where we escape everything as

macro toodirty_elapsed(ex)
	ex = quote
		tstart = time()
		$(ex)
		time() - tstart
	end
	esc(ex)
end

let 
	tstart = "should not change the value and type "
	t = @toodirty_elapsed r = fib(10)
	println("the evaluation of fib took ", t, "s and result is ", r)
	println(tstart, "  ", typeof(tstart))
end

Using @macroexpand we observe that @toodirty_elapsed does not have any trace of hygiene.

julia> Base.remove_linenums!(@macroexpand @toodirty_elapsed r = fib(10))
quote
    tstart = time()
    r = fib(10)
    time() - tstart
end

From the above we can also see that hygiene-pass occurs after the macro has been applied but before the code is lowered. esc is inserted to AST as a special node Expr(:escape,...), which can be seen from the follows.

julia> esc(:x)
:($(Expr(:escape, :x)))

The definition in essentials.jl:480 is pretty simple as esc(@nospecialize(e)) = Expr(:escape, e), but it does not tell anything about the actual implementation, which is hidden probably in the macro-expanding logic.

With that in mind, we can now understand our original example with @replace_sin. Recall that we have defined it as

macro replace_sin(ex)
	replace_sin(esc(ex))
end

where the escaping replace_sin(esc(ex)) in communicates to compiler that ex should be used as without hygienating the ex. Indeed, if we lower it

function cosp2(x)
	@replace_sin 2 + sin(x)
end

julia> @code_lowered(cosp2(1.0))
CodeInfo(
1 ─ %1 = Main.cos(x)
│   %2 = 2 + %1
└──      return %2
)

we see it works as intended. Whereas if we use hygienic version

macro hygienic_replace_sin(ex)
	replace_sin(ex)
end

function hcosp2(x)
	@hygienic_replace_sin 2 + sin(x)
end

julia> @code_lowered(hcosp2(1.0))
CodeInfo(
1 ─ %1 = Main.cos(Main.x)
│   %2 = 2 + %1
└──      return %2
)

Why hygienating the function calls?

function foo(x)
	cos(x) = exp(x)
	@replace_sin 1 + sin(x)
end

foo(1.0) ≈ 1 + exp(1.0)

function foo2(x)
	cos(x) = exp(x)
	@hygienic_replace_sin 1 + sin(x)
end

x = 1.0
foo2(1.0) ≈ 1 + cos(1.0)

Can I do the hygiene by myself?

Yes, it is by some considered to be much simpler (and safer) then to understand, how macro hygiene works.

macro manual_elapsed(ex)
    x = gensym()
    esc(quote
    		$(x) = time()
        	$(ex)
        	time() - $(x)
        end
    )
end

let 
	t = @manual_elapsed r = fib(10)
	println("the evaluation of fib took ", t, "s and result is ", r)
end

How macros compose?

macro m1(ex)
	println("m1: ")
	dump(ex)
	ex
end

macro m2(ex)
	println("m2: ")
	dump(ex)
	esc(ex)
end

@m1 @m2 1 + sin(1)

which means that macros are expanded in the order from the outer most to inner most, which is exactly the other way around than functions.

@macroexpand @m1 @m2 1 + sin(1)

also notice that the escaping is only partial (running @macroexpand @m2 @m1 1 + sin(1) would not change the results).

Write @exfiltrate macro

Since Julia's debugger is a complicated story, people have been looking for tools, which would simplify the debugging. One of them is a macro @exfiltrate, which copies all variables in a given scope to a safe place, from where they can be collected later on. This helps you in evaluating the function. F

Whyle a full implementation is provided in package Infiltrator.jl, we can implement such functionality by outselves.

• We collect names and values of variables in a given scope using the macro Base.@locals
• We store variables in some global variable in some module, such that we have one place from which we can retrieve them and we are certain that this storage would not interact with any existing code.
• If the @exfiltrate should be easy, ideally called without parameters, it has to be implemented as a macro to supply the relevant variables to be stored.

module Exfiltrator

const environment = Dict{Symbol, Any}()

function copy_variables!(d::Dict)
	foreach(k -> delete!(environment, k), keys(environment))
	for (k, v) in d
		environment[k] = v
	end
end

macro exfiltrate()
	v = gensym(:vars)
	quote
		$(v) = $(esc((Expr(:locals))))
		copy_variables!($(v))
	end
end

end

Test it to

using Main.Exfiltrator: @exfiltrate
let 
	x,y,z = 1,"hello", (a = "1", b = "b")
	@exfiltrate
end

Exfiltrator.environment

function inside_function()
	a,b,c = 1,2,3
	@exfiltrate
end

inside_function()

Exfiltrator.environment

function a()
	a = 1
	@exfiltrate
end

function b()
	b = 1
	a()
end
function c()
	c = 1
	b()
end

c()
Exfiltrator.environment

Domain Specific Languages (DSL)

Macros are convenient for writing domain specific languages, which are languages designed for specific domain. This allows them to simplify notation and / or make the notation familiar for people working in the field. For example in Turing.jl, the model of coinflips can be specified as

@model function coinflip(y)

    # Our prior belief about the probability of heads in a coin.
    p ~ Beta(1, 1)

    # The number of observations.
    N = length(y)
    for n in 1:N
        # Heads or tails of a coin are drawn from a Bernoulli distribution.
        y[n] ~ Bernoulli(p)
    end
end;

which resembles, but not copy Julia's syntax due to the use of ~. A similar DSLs can be seen in ModelingToolkit.jl for differential equations, in Soss.jl again for expressing probability problems, in Metatheory.jl / SymbolicUtils.jl for defining rules on elements of algebras, or JuMP.jl for specific mathematical programs.

One of the reasons for popularity of DSLs is that macro system is very helpful in their implementation, but it also contraints the DSL, as it has to be parseable by Julia's parser. This is a tremendous helps, because one does not have to care about how to parse numbers, strings, parenthesess, functions, etc. (recall the last lecture about replacing occurences of i variable).

Let's jump into the first example adapted from John Myles White's howto. We would like to write a macro, which allows us to define graph in Graphs.jl just by defining edges.

@graph begin 
	1 -> 2
	2 -> 3
	3 -> 1
end

The above should expand to

using Graphs
g = DiGraph(3)
add_edge!(g, 1,2)
add_edge!(g, 2,3)
add_edge!(g, 3,1)
g

Let's start with easy and observe, how

ex = Meta.parse("""
begin 
	1 -> 2
	2 -> 3
	3 -> 1
end
""")
ex = Base.remove_linenums!(ex)

is parsed to

quote
    1->begin
            2
        end
    2->begin
            3
        end
    3->begin
            1
        end
end

We see that

• the sequence of statements is parsed to block (we know that from last lecture).
• -> is parsed to ->, i.e. ex.args[1].head == :-> with parameters being the first vertex ex.args[1].args[1] == 1 and the second vertex is quoted to ex.args[1].args[2].head == :block.

The main job will be done in the function parse_edge, which will parse one edge. It will check that the node defines edge (otherwise, it will return nothing, which will be filtered out)

function parse_edge(ex)
	#checking the syntax
	!hasproperty(ex, :head) && return(nothing)
	!hasproperty(ex, :args) && return(nothing)
	ex.head != :-> && return(nothing)
	length(ex.args) != 2 && return(nothing)
	!hasproperty(ex.args[2], :head) && return(nothing)
	ex.args[2].head != :block && length(ex.args[2].args) == 1 && return(nothing)

	#ready to go
	src = ex.args[1]
	@assert src isa Integer
	dst = ex.args[2].args[1]
	@assert dst isa Integer
	:(add_edge!(g, $(src), $(dst)))
end

function parse_graph(ex)
	@assert ex.head == :block
	ex = Base.remove_linenums!(ex)
	edges = filter(!isnothing, parse_edge.(ex.args))
	n = maximum(e -> maximum(e.args[3:4]), edges)
	quote
       g = Graphs.DiGraph($(n))
       $(edges...)
       g
   end
end

Once we have the first version, let's make everything hygienic

function parse_edge(g, ex::Expr)
	#checking the syntax
	ex.head != :-> && return(nothing)
	length(ex.args) != 2 && return(nothing)
	!hasproperty(ex.args[2], :head) && return(nothing)
	ex.args[2].head != :block && length(ex.args[2].args) == 1 && return(nothing)

	#ready to go
	src = ex.args[1]
	@assert src isa Integer
	dst = ex.args[2].args[1]
	@assert dst isa Integer
	:(add_edge!($(g), $(src), $(dst)))
end
parse_edge(g, ex) = nothing

function parse_graph(ex)
	@assert ex.head == :block
	g = gensym(:graph)
	ex = Base.remove_linenums!(ex)
	edges = filter(!isnothing, parse_edge.(g, ex.args))
	n = maximum(e -> maximum(e.args[3:4]), edges)
	quote
       $(g) = Graphs.DiGraph($(n))
       $(edges...)
       $(g)
   end
end

and we are ready to go

macro graph(ex)
	parse_graph(ex)
end

@graph begin
	1 -> 2
	2 -> 3
	3 -> 1
end

and we can check the output with @macroexpand.

julia> @macroexpand @graph begin
               1 -> 2
               2 -> 3
               3 -> 1
       end
quote
    #= REPL[173]:8 =#
    var"#27###graph#273" = (Main.Graphs).DiGraph(3)
    #= REPL[173]:9 =#
    Main.add_edge!(var"#27###graph#273", 1, 2)
    Main.add_edge!(var"#27###graph#273", 2, 3)
    Main.add_edge!(var"#27###graph#273", 3, 1)
    #= REPL[173]:10 =#
    var"#27###graph#273"
end

non-standard string literals

Julia allows to customize parsing of strings. For example we can define regexp matcher as r"^\s*(?:#|$)", i.e. using the usual string notation prepended by the string r.

You can define these "parsers" by yourself using the macro definition with suffix _str

macro debug_str(p)
	@show p
    p
end

by invoking it

debug"hello"

we see that the string macro receives string as an argument.

Why are they useful? Sometimes, we want to use syntax which is not compatible with Julia's parser. For example IntervalArithmetics.jl allows to define an interval open only from one side, for example [a, b), which is something that Julia's parser would not like much. String macro solves this problem by letting you to write the parser by your own.

struct Interval{T}
	left::T
	right::T
	left_open::Bool
	right_open::Bool
end

function Interval(s::String)
	s[1] == '(' || s[1] == '[' || error("left nterval can be only [,(")
	s[end] == ')' || s[end] == ']' || error("left nterval can be only ],)")
 	left_open = s[1] == '(' ? true : false
 	right_open = s[end] == ')' ? true : false
 	ss = parse.(Float64, split(s[2:end-1],","))
 	length(ss) != 2 && error("interval should have two numbers separated by ','")
 	Interval(ss..., left_open, right_open)
end

function Base.show(io::IO, r::Interval)
	lb = r.left_open ? "(" : "["
	rb = r.right_open ? ")" : "]"
	print(io, lb,r.left,",",r.right,rb)
end

We can check it does the job by trying Interval("[1,2)"). Finally, we define a string macro as

macro int_str(s)
	Interval(s)
end

which allows us to define interval as int"[1,2)".

Sources

• Great discussion on evaluation of macros.